# HowTo:Use Modular Numbers

From CoCoAWiki

## Question

What's wrong in this?

Use R::=Z/(5)[x]; 5x+2y; 2y ------------------------------- 5=0; FALSE -------------------------------

Moreover this command throws an error

Use R::=Z/(5);

## Answer

Type(5); INT -------------------------------

5 is an integer, and integers do not depend on the current ring: could you imagine what would happen to a For cycle over Z/(2)? ;-)

If you want to use 5 as a modular number you should either use this syntax (similar to C/C++)

5 % 5; 0 % 5 -------------------------------

or embed your integer into the polynomial ring

Use R::=Z/(5)[x]; Poly(5); 0 -------------------------------

The creation of a polynomial ring with no indeterminated has been disabled to highlight this (unexpected?) behaviour.