# ApCoCoA-1:LinAlg.REF

## LinAlg.REF

Compute a row echelon form.

### Syntax

LinAlg.REF(M:MAT, CompRREF:BOOL):MAT LinAlg.REF(M:MAT, P:INT, CompRREF:BOOL):MAT

### Description

**Please note:** The function(s) explained on this page is/are using the **ApCoCoAServer**. You will have to start the ApCoCoAServer in order to use

it/them.

This function allows you to compute a (reduced) row echelon form of a matrix `M` defined over a field. If you want to use the first version without the parameter `P`, the components of the input matrix `M` must be castable to type `RAT` and your current working ring must be the same ring over which `M` has been defined. The second version of this function lets you compute a (reduced) row echelon form of `M` mod `P` and the components of `M` must be of type `INT`.

The parameter `CompRREF` lets you specify if you want to compute a row echelon form or the reduced row echelon form of `M`. If `CompRREF` is set to `TRUE`, the reduced row echelon form will be computed, and if it is set to `FALSE`, a row echelon form where all pivot elements are equal to one will be computed.

The return value of both functions is the computed (reduced) row echelon form of `M`.

@param

*M*A matrix whose (reduced) row echelon form to compute. If parameter P is given, the components of M must be of type INT. Otherwise, they must be castable to type RAT.@param

*P*An integer value. If P is specified, the (reduced) row echelon form computation will be carried out over the ring Z/pZ.@param

*CompRREF*Set to*TRUE*if you want to compute the reduced row echelon form of M or to`FALSE`otherwise.@return A (reduced) row echelon form of M.

#### Example

Use Q[x,y]; M := Mat([[ 1/2, 1/3, 2], [200, 3000, 1], [2, 5, 17], [1, 1, 1]]); M; LinAlg.REF(M, FALSE); Mat([ [1/2, 1/3, 2], [200, 3000, 1], [2, 5, 17], [1, 1, 1] ]) ------------------------------- Mat([ [1, 2/3, 4], [0, 1, -2397/8600], [0, 0, 1], [0, 0, 0] ]) ------------------------------- Use Q[x,y]; M := Mat([[ 1, 1, 2], [200, 3000, 1], [2, 5, 17], [1, 1, 1]]); M; LinAlg.REF(M, 17, TRUE); Mat([ [1, 1, 2], [200, 3000, 1], [2, 5, 17], [1, 1, 1] ]) ------------------------------- Mat([ [1, 0, 0], [0, 1, 0], [0, 0, 1], [0, 0, 0] ]) -------------------------------