Difference between revisions of "ApCoCoA-1:DA.LPot"

From ApCoCoAWiki
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<command>
 
<command>
     <title>diffalg.LPot</title>
+
     <title>DA.LPot</title>
     <short_description>the leading power of a differential polynomial</short_description>
+
     <short_description>Computes the leading power of a differential polynomial.</short_description>
 
<syntax>
 
<syntax>
$diffalg.LPot(F:POLY):POLY
+
DA.LPot(F:POLY):POLY
 
</syntax>
 
</syntax>
 
<description>
 
<description>
LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.
+
DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.
 +
<itemize>
 +
<item>@param F A differential polynomial.</item>
 +
<item>@return The leading power of F.</item>
 +
</itemize>
 
<example>
 
<example>
 
Use Q[x[1..2,0..20]];
 
Use Q[x[1..2,0..20]];
Use Q[x[1..2,0..20]], Ord($diffalg.DiffTO("Lex"));
+
Use Q[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
$diffalg.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
+
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
 
-------------------------------
 
-------------------------------
 
x[1,2]^2
 
x[1,2]^2
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</example>
 
</example>
 
</description>
 
</description>
<see>Diffalg.DiffTO</see>
+
<types>
 +
<type>polynomial</type>
 +
</types>
 +
<see>DA.DiffTO</see>
 +
<key>LPot</key>
 +
<key>DA.LPot</key>
 +
<key>diffalg.LPot</key>
 +
<key>differential.LPot</key>
 
<wiki-category>Package_diffalg</wiki-category>
 
<wiki-category>Package_diffalg</wiki-category>
 
</command>
 
</command>

Revision as of 13:38, 22 April 2009

DA.LPot

Computes the leading power of a differential polynomial.

Syntax

DA.LPot(F:POLY):POLY

Description

DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.

  • @param F A differential polynomial.

  • @return The leading power of F.

Example

Use Q[x[1..2,0..20]];
Use Q[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
-------------------------------
x[1,2]^2
-------------------------------

DA.DiffTO