Difference between revisions of "ApCoCoA-1:BBF.Steps"

From ApCoCoAWiki
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<command>
 
<command>
 
   <title>BBF.Steps</title>
 
   <title>BBF.Steps</title>
   <short_description>Execute border basis computation steps.</short_description>
+
   <short_description>Executes border basis computation steps.</short_description>
 
    
 
    
 
<syntax>
 
<syntax>
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<em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them.
 
<em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them.
 
<par/>
 
<par/>
Execute <tt>NumOfSteps</tt> &gt; 0 computation steps of the Border Basis Algorithm on ApCoCoABBFServer.
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This command executes <tt>NumOfSteps</tt> &gt; 0 computation steps of the Border Basis Algorithm on ApCoCoABBFServer.
 
<itemize>
 
<itemize>
 
   <item>@param <em>NumOfSteps</em> The number of computation steps to execute.</item>
 
   <item>@param <em>NumOfSteps</em> The number of computation steps to execute.</item>

Revision as of 14:27, 8 July 2009

BBF.Steps

Executes border basis computation steps.

Syntax

BBF.Steps(NumOfSteps:INT):STRING

Description

Please note: The function(s) explained on this page is/are using the ApCoCoABBFServer. You will have to start the ApCoCoABBFServer in order to use it/them.

This command executes NumOfSteps > 0 computation steps of the Border Basis Algorithm on ApCoCoABBFServer.

  • @param NumOfSteps The number of computation steps to execute.

  • @return A status string.

Example

Use ZZ/(32003)[x, y, z],DegLex;
I:=Ideal(-4*x^2, -4*y^2, 5*z^2);
BBF.Init(I);
BBF.Steps(3);
Computation started.

-------------------------------

BB.BBasis