ApCoCoA-1:BBF.Steps: Difference between revisions
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<command> | <command> | ||
<title>BBF.Steps</title> | <title>BBF.Steps</title> | ||
<short_description> | <short_description>Executes border basis computation steps.</short_description> | ||
<syntax> | <syntax> | ||
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<em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them. | <em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them. | ||
<par/> | <par/> | ||
This command executes <tt>NumOfSteps</tt> > 0 computation steps of the Border Basis Algorithm on ApCoCoABBFServer. | |||
<itemize> | <itemize> | ||
<item>@param <em>NumOfSteps</em> The number of computation steps to execute.</item> | <item>@param <em>NumOfSteps</em> The number of computation steps to execute.</item> | ||
Revision as of 14:27, 8 July 2009
BBF.Steps
Executes border basis computation steps.
Syntax
BBF.Steps(NumOfSteps:INT):STRING
Description
Please note: The function(s) explained on this page is/are using the ApCoCoABBFServer. You will have to start the ApCoCoABBFServer in order to use it/them.
This command executes NumOfSteps > 0 computation steps of the Border Basis Algorithm on ApCoCoABBFServer.
@param NumOfSteps The number of computation steps to execute.
@return A status string.
Example
Use ZZ/(32003)[x, y, z],DegLex; I:=Ideal(-4*x^2, -4*y^2, 5*z^2); BBF.Init(I); BBF.Steps(3); Computation started. -------------------------------
