ApCoCoA-1:Slinalg.SEF

Slinalg.SEF

Computes the row echelon form of a sparse matrix over F2.

Syntax

Slinalg.SEF(NRow:INT, NCol:INT, M:LIST): LIST 
Slinalg.SEF_v2(NRow:INT, NCol:INT, M:LIST): LIST 

Description

Please note: The function(s) explained on this page is/are using the ApCoCoAServer. You will have to start the ApCoCoAServer in order to use it/them.

Both fucntions calculate the echelon form of a matrix. Difference is that the second one scan through all the rows and select the row with fewer number of no zero elements to select the piviot element. Therefore, second one is more efficient than the first one.

• @param NRow: Number of rows of the matrix.

• @param NCol: Number of Columns of the matrix.

• @param M: List of lists containing positions of non zero elements.

• @return A list of lists containing the row echelon form of the matrix M.

Example

Use ZZ/(2)[x];
NRow:=10;
NCol:=13;
M := [[1, 2, 6, 7],
      [1, 2, 4, 5, 6], 
      [2, 3], 
      [2, 3, 10, 11], 
      [2, 4, 6, 7, 9, 10], 
      [2, 10, 11, 13], 
      [5, 6, 8],
      [ 6, 8, 9,10,12],
      [6, 10, 12], 
      [10, 13]];

Slinalg.SEF(NRow, NCol, M);
[[1,2,6,7],
 [2,3],
 [3,4,6,7,9,10],
 [4,5,7],
 [5,6,8],
 [6,8,9,10,12],
 [8,9,11,13],
 [10,11],
 [11,13]]
	
-------------------------------

Example

Use ZZ/(2)[x];
NRow:=10;
NCol:=13;
M := [[1, 2, 6, 7],
      [1, 2, 4, 5, 6], 
      [2, 3], 
      [2, 3, 10, 11], 
      [2, 4, 6, 7, 9, 10], 
      [2, 10, 11, 13], 
      [5, 6, 8],
      [ 6, 8, 9,10,12],
      [6, 10, 12], 
      [10, 13]];

Slinalg.SEF_v2(NRow, NCol, M);
[[1, 2, 6, 7],
 [2, 3],
 [3, 10, 11, 13],
 [4, 5, 7],
 [5, 6, 8],
 [6, 10, 12],
 [8, 9],
 [10, 11],
 [11, 13]]

-------------------------------

See also

Introduction to CoCoAServer

IML.REF

LinAlg.REF