Difference between revisions of "ApCoCoA-1:BBF.RetrieveVPolysWithTermInSupport"
From ApCoCoAWiki
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<command> | <command> | ||
<title>BBF.RetrieveVPolysWithTermInSupport</title> | <title>BBF.RetrieveVPolysWithTermInSupport</title> | ||
− | <short_description> | + | <short_description>Retrieves polynomials with specific support term from <tt>V</tt>.</short_description> |
<syntax> | <syntax> | ||
Line 9: | Line 9: | ||
<em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them. | <em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoABBFServer</em>. You will have to start the ApCoCoABBFServer in order to use it/them. | ||
<par/> | <par/> | ||
− | + | This command retrieves all polynomials from <tt>V</tt> that have the term <tt>T</tt> in their support. | |
<itemize> | <itemize> | ||
− | <item>@param <em>T</em> All polynomials in V with this term in their support will be | + | <item>@param <em>T</em> All polynomials in <tt>V</tt> with this term in their support will be retrieved.</item> |
− | <item>@return List of polynomials of set V.</item> | + | <item>@return List of polynomials of set <tt>V</tt>.</item> |
</itemize> | </itemize> | ||
<example> | <example> |
Revision as of 14:20, 8 July 2009
BBF.RetrieveVPolysWithTermInSupport
Retrieves polynomials with specific support term from V.
Syntax
BBF.RetrieveVPolysWithTermInSupport(T:POLY):LIST
Description
Please note: The function(s) explained on this page is/are using the ApCoCoABBFServer. You will have to start the ApCoCoABBFServer in order to use it/them.
This command retrieves all polynomials from V that have the term T in their support.
@param T All polynomials in V with this term in their support will be retrieved.
@return List of polynomials of set V.
Example
Use ZZ/(32003)[x, y, z],DegLex; I:=Ideal(-4*x^2 + 1, -4*y^2 - 1, 5*z^2); BBF.Init(I); BBF.Steps(20); -- After computation has finished: BBF.RetrieveVPolysWithTermInSupport(z); Output: [x^2z - 8001z, y^2z + 8001z]
BBF.Explanation of BBF variables and structures