Difference between revisions of "ApCoCoA-1:DA.LPot"
From ApCoCoAWiki
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<command> | <command> | ||
| − | <title> | + | <title>DA.LPot</title> |
| − | <short_description>the leading power of a differential polynomial</short_description> | + | <short_description>Computes the leading power of a differential polynomial.</short_description> |
<syntax> | <syntax> | ||
| − | + | DA.LPot(F:POLY):POLY | |
</syntax> | </syntax> | ||
<description> | <description> | ||
| − | LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively. | + | DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively. |
| + | <itemize> | ||
| + | <item>@param F A differential polynomial.</item> | ||
| + | <item>@return The leading power of F.</item> | ||
| + | </itemize> | ||
<example> | <example> | ||
Use Q[x[1..2,0..20]]; | Use Q[x[1..2,0..20]]; | ||
| − | Use Q[x[1..2,0..20]], Ord( | + | Use Q[x[1..2,0..20]], Ord(DA.DiffTO("Lex")); |
| − | + | DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]); | |
------------------------------- | ------------------------------- | ||
x[1,2]^2 | x[1,2]^2 | ||
| Line 16: | Line 20: | ||
</example> | </example> | ||
</description> | </description> | ||
| − | <see> | + | <types> |
| + | <type>polynomial</type> | ||
| + | </types> | ||
| + | <see>DA.DiffTO</see> | ||
| + | <key>LPot</key> | ||
| + | <key>DA.LPot</key> | ||
| + | <key>diffalg.LPot</key> | ||
| + | <key>differential.LPot</key> | ||
<wiki-category>Package_diffalg</wiki-category> | <wiki-category>Package_diffalg</wiki-category> | ||
</command> | </command> | ||
Revision as of 13:38, 22 April 2009
DA.LPot
Computes the leading power of a differential polynomial.
Syntax
DA.LPot(F:POLY):POLY
Description
DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.
@param F A differential polynomial.
@return The leading power of F.
Example
Use Q[x[1..2,0..20]];
Use Q[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
-------------------------------
x[1,2]^2
-------------------------------
