Difference between revisions of "ApCoCoA-1:Slinalg.SGEF"
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<em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoAServer</em>. You will have to start the ApCoCoAServer in order to use it/them. | <em>Please note:</em> The function(s) explained on this page is/are using the <em>ApCoCoAServer</em>. You will have to start the ApCoCoAServer in order to use it/them. | ||
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'''Structured Gaussian Elimination:''' Structured Gaussian Elimination has the following four steps: | '''Structured Gaussian Elimination:''' Structured Gaussian Elimination has the following four steps: | ||
− | (1) | + | (1) Delete all columns that have a single non-zero coefficient and the rows in which those columns have non-zero coefficients. |
− | + | (2) Declare some additional light columns to be heavy, chossing the heaviest ones. | |
− | + | (3) Delete some of the rows, selecting those which have the largest number of non-zero elements in the light columns. | |
− | + | (4) For any row which has only a single non-zero coefficient equal to 1 in the light column, subtract appropriate multiples of that row from all other rows that have non-zero coefficients on that column so as to make those coefficients 0. | |
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Revision as of 11:31, 6 October 2009
Slinalg.SGEF
Computes the row echelon form of a sparse matrix over F2 using structured Gaussian Elimination.
Syntax
Slinalg.SSEF(NRow : INT ,NCol : INT, Mat : LIST, CSteps: STRING): LIST of LIST
Description
Please note: The function(s) explained on this page is/are using the ApCoCoAServer. You will have to start the ApCoCoAServer in order to use it/them.
Structured Gaussian Elimination: Structured Gaussian Elimination has the following four steps:
(1) Delete all columns that have a single non-zero coefficient and the rows in which those columns have non-zero coefficients.
(2) Declare some additional light columns to be heavy, chossing the heaviest ones. (3) Delete some of the rows, selecting those which have the largest number of non-zero elements in the light columns. (4) For any row which has only a single non-zero coefficient equal to 1 in the light column, subtract appropriate multiples of that row from all other rows that have non-zero coefficients on that column so as to make those coefficients 0.
@param NRow: Number of rows of the matrix.
@param NCol: Number of Columns of the matrix.
@param Mat: List of lists containing positions of non zero elements.
@return A list of lists containing the row echelon form of the matrix.
Example
Use ZZ/(2)[x]; NRow:=10; NCol:=13; M := [[1, 2, 6, 7], [1, 2, 4, 5, 6], [2, 3], [2, 3, 10, 11], [2, 4, 6, 7, 9, 10], [2, 10, 11, 13], [5, 6, 8], [ 6, 8, 9,10,12], [6, 10, 12], [10, 13]]; Slinalg.SEF(NRow, NCol, M); [[1,2,6,7], [2,3], [3,4,6,7,9,10], [4,5,7], [5,6,8], [6,8,9,10,12], [8,9,11,13], [10,11], [11,13]] -------------------------------
See also