Difference between revisions of "ApCoCoA-1:DA.Initial"
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S schuster (talk | contribs) m (ApCoCoA:Diffalg.Initial moved to ApCoCoA:DA.Initial: To comply with style principles.) |
m (replaced <quotes> tag by real quotes) |
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+ | {{Version|1}} | ||
<command> | <command> | ||
<title>DA.Initial</title> | <title>DA.Initial</title> | ||
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</syntax> | </syntax> | ||
<description> | <description> | ||
− | Initial returns the initial of polynomial F wrt. the current differential term ordering, or the hereby induced ranking, respectively. | + | <ref>ApCoCoA-1:DA.Initial|DA.Initial</ref> returns the initial of polynomial <tt>F</tt> wrt. the current differential term ordering, or the hereby induced ranking, respectively. |
<itemize> | <itemize> | ||
− | <item>@param F A differential polynomial.</item> | + | <item>@param <em>F</em> A differential polynomial.</item> |
− | <item>@return The initial of F.</item> | + | <item>@return The initial of <tt>F</tt>.</item> |
</itemize> | </itemize> | ||
<example> | <example> | ||
− | Use | + | Use QQ[x[1..2,0..20]]; |
− | Use | + | Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex")); |
F:=x[1,2]^3x[2,2]^2 + x[1,1]^3x[2,2]^2 + 1/4x[1,2]; | F:=x[1,2]^3x[2,2]^2 + x[1,1]^3x[2,2]^2 + 1/4x[1,2]; | ||
Line 34: | Line 35: | ||
<type>polynomial</type> | <type>polynomial</type> | ||
</types> | </types> | ||
− | <see>DA.LD</see> | + | <see>ApCoCoA-1:DA.LD|DA.LD</see> |
− | <see>DA.LPot</see> | + | <see>ApCoCoA-1:DA.LPot|DA.LPot</see> |
− | <see>DA.DiffTO</see> | + | <see>ApCoCoA-1:DA.DiffTO|DA.DiffTO</see> |
+ | |||
<key>Initial</key> | <key>Initial</key> | ||
<key>DA.Initial</key> | <key>DA.Initial</key> | ||
<key>diffalg.Initial</key> | <key>diffalg.Initial</key> | ||
<key>differential.Initial</key> | <key>differential.Initial</key> | ||
− | <wiki-category>Package_diffalg</wiki-category> | + | <wiki-category>ApCoCoA-1:Package_diffalg</wiki-category> |
</command> | </command> |
Latest revision as of 13:29, 29 October 2020
This article is about a function from ApCoCoA-1. |
DA.Initial
Computes the initial of a differential polynomial.
Syntax
DA.Initial(F:POLY):POLY
Description
DA.Initial returns the initial of polynomial F wrt. the current differential term ordering, or the hereby induced ranking, respectively.
@param F A differential polynomial.
@return The initial of F.
Example
Use QQ[x[1..2,0..20]]; Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex")); F:=x[1,2]^3x[2,2]^2 + x[1,1]^3x[2,2]^2 + 1/4x[1,2]; DA.LD(F); ------------------------------- x[2,2] ------------------------------- DA.LPot(F); ------------------------------- x[2,2]^2 ------------------------------- DA.Initial(F); ------------------------------- x[1,2]^3 + x[1,1]^3 -------------------------------