Difference between revisions of "ApCoCoA-1:BB.Border"

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{{Version|1}}
 
<command>
 
<command>
    <title>BB.Border</title>
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  <title>BB.Border</title>
    <short_description>border of an order ideal</short_description>
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  <short_description>Computes the border of an order ideal.</short_description>
 +
 
 
<syntax>
 
<syntax>
 
BB.Border(OO:LIST):LIST
 
BB.Border(OO:LIST):LIST
 
</syntax>
 
</syntax>
    <description>
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  <description>
Computes the border of an order ideal OO. The input/output is a list of terms.
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This command computes the border of an order ideal <tt>OO</tt>.
<example>
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<itemize>
Use Q[x,y,z];
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  <item>@param <em>OO</em> A list of terms representing an order ideal.</item>
 +
  <item>@return A list of border terms of <tt>OO</tt> in ascending order.</item>
 +
</itemize>
 +
<example>Use QQ[x,y,z];
 
BB.Border([1,x]);
 
BB.Border([1,x]);
 +
 
[z, y, xz, xy, x^2]
 
[z, y, xz, xy, x^2]
 
-------------------------------
 
-------------------------------
 
</example>
 
</example>
    </description>
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  </description>
     <see>BBasis</see>
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  <types>
     <see>BB.BorderBasis</see>
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     <type>borderbasis</type>
    <see>BB.Box</see>
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     <type>ideal</type>
    <see>Category:Package borderbasis</see>
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  </types>
    <key>kreuzer</key>
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  <see>ApCoCoA-1:BB.BBasis|BB.BBasis</see>
    <key>bb.border</key>
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  <see>ApCoCoA-1:BB.BorderBasis|BB.BorderBasis</see>
    <key>borderbasis.border</key>
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  <see>ApCoCoA-1:BB.Box|BB.Box</see>
    <wiki-category>Package_borderbasis</wiki-category>
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 +
  <key>Border</key>
 +
  <key>BB.Border</key>
 +
  <key>borderbasis.Border</key>
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  <wiki-category>ApCoCoA-1:Package_borderbasis</wiki-category>
 
</command>
 
</command>

Latest revision as of 09:39, 7 October 2020

This article is about a function from ApCoCoA-1.

BB.Border

Computes the border of an order ideal.

Syntax

BB.Border(OO:LIST):LIST

Description

This command computes the border of an order ideal OO.

  • @param OO A list of terms representing an order ideal.

  • @return A list of border terms of OO in ascending order.

Example

Use QQ[x,y,z];
BB.Border([1,x]);

[z, y, xz, xy, x^2]
-------------------------------

BB.BBasis

BB.BorderBasis

BB.Box