ApCoCoA-1:DA.LPot: Difference between revisions

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{{Version|1}}
<command>
<command>
     <title>diffalg.LPot</title>
     <title>DA.LPot</title>
     <short_description>the leading power of a differential polynomial</short_description>
     <short_description>Computes the leading power of a differential polynomial.</short_description>
<syntax>
<syntax>
$diffalg.LPot(F:POLY):POLY
DA.LPot(F:POLY):POLY
</syntax>
</syntax>
<description>
<description>
LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.
<ref>ApCoCoA-1:DA.LPot|DA.LPot</ref> returns the leading power of polynomial <tt>F</tt> wrt. the current differential term order, or the hereby induced ranking respectively.
<itemize>
<item>@param <em>F</em> A differential polynomial.</item>
<item>@return The leading power of <tt>F</tt>.</item>
</itemize>
<example>
<example>
Use Q[x[1..2,0..20]];
Use QQ[x[1..2,0..20]];
Use Q[x[1..2,0..20]], Ord($diffalg.DiffTO("Lex"));
Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
$diffalg.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
-------------------------------
-------------------------------
x[1,2]^2
x[1,2]^2
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</example>
</example>
</description>
</description>
<see>Diffalg.DiffTO</see>
<types>
<wiki-category>Package_diffalg</wiki-category>
<type>polynomial</type>
</types>
<see>ApCoCoA-1:DA.DiffTO|DA.DiffTO</see>
 
<key>LPot</key>
<key>DA.LPot</key>
<key>diffalg.LPot</key>
<key>differential.LPot</key>
<wiki-category>ApCoCoA-1:Package_diffalg</wiki-category>
</command>
</command>

Latest revision as of 13:30, 29 October 2020

This article is about a function from ApCoCoA-1.

DA.LPot

Computes the leading power of a differential polynomial.

Syntax

DA.LPot(F:POLY):POLY

Description

DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.

  • @param F A differential polynomial.

  • @return The leading power of F.

Example

Use QQ[x[1..2,0..20]];
Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
-------------------------------
x[1,2]^2
-------------------------------

DA.DiffTO