Difference between revisions of "ApCoCoA-1:DA.LPot"
From ApCoCoAWiki
m (fixed links to namespace ApCoCoA) |
m (replaced <quotes> tag by real quotes) |
||
| (One intermediate revision by the same user not shown) | |||
| Line 1: | Line 1: | ||
| + | {{Version|1}} | ||
<command> | <command> | ||
<title>DA.LPot</title> | <title>DA.LPot</title> | ||
| Line 13: | Line 14: | ||
<example> | <example> | ||
Use QQ[x[1..2,0..20]]; | Use QQ[x[1..2,0..20]]; | ||
| − | Use QQ[x[1..2,0..20]], Ord(DA.DiffTO( | + | Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex")); |
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]); | DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]); | ||
------------------------------- | ------------------------------- | ||
Latest revision as of 13:30, 29 October 2020
| This article is about a function from ApCoCoA-1. |
DA.LPot
Computes the leading power of a differential polynomial.
Syntax
DA.LPot(F:POLY):POLY
Description
DA.LPot returns the leading power of polynomial F wrt. the current differential term order, or the hereby induced ranking respectively.
@param F A differential polynomial.
@return The leading power of F.
Example
Use QQ[x[1..2,0..20]];
Use QQ[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
DA.LPot(x[1,1]^2x[1,2]^2 + 1/4x[1,2]);
-------------------------------
x[1,2]^2
-------------------------------
