Difference between revisions of "ApCoCoA-1:DA.Initial"
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Initial returns the initial of polynomial F wrt. the current differential term ordering, or the hereby induced ranking, respectively. | Initial returns the initial of polynomial F wrt. the current differential term ordering, or the hereby induced ranking, respectively. | ||
<itemize> | <itemize> | ||
| − | <item>@param F A differential polynomial.</item> | + | <item>@param <em>F</em> A differential polynomial.</item> |
<item>@return The initial of F.</item> | <item>@return The initial of F.</item> | ||
</itemize> | </itemize> | ||
| Line 37: | Line 37: | ||
<see>DA.LPot</see> | <see>DA.LPot</see> | ||
<see>DA.DiffTO</see> | <see>DA.DiffTO</see> | ||
| + | |||
<key>Initial</key> | <key>Initial</key> | ||
<key>DA.Initial</key> | <key>DA.Initial</key> | ||
Revision as of 11:04, 23 April 2009
DA.Initial
Computes the initial of a differential polynomial.
Syntax
DA.Initial(F:POLY):POLY
Description
Initial returns the initial of polynomial F wrt. the current differential term ordering, or the hereby induced ranking, respectively.
@param F A differential polynomial.
@return The initial of F.
Example
Use Q[x[1..2,0..20]];
Use Q[x[1..2,0..20]], Ord(DA.DiffTO("Lex"));
F:=x[1,2]^3x[2,2]^2 + x[1,1]^3x[2,2]^2 + 1/4x[1,2];
DA.LD(F);
-------------------------------
x[2,2]
-------------------------------
DA.LPot(F);
-------------------------------
x[2,2]^2
-------------------------------
DA.Initial(F);
-------------------------------
x[1,2]^3 + x[1,1]^3
-------------------------------
